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Shake lua

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Shake lua

17 replies

Shake lua

J4x
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03.06.11 03:15:49 am

Hi, I was making this script, and i end up with this error:
'end' expected (to close 'function' at line 2) near 'elseif'
I know that it means that I should add another end before elseif, but I don't know why it happens...

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addhook("hit","shake")
function shake(id,source,weapon)
	if itemtype(type,"dmg") >= 20 then
	parse("shake "..id.." 10")
end	
	elseif
	itemtype(type,"dmg") <= 19 then
	parse("shake "..id.." 5")
	end
end

edited 1×, last 04.06.11 02:26:27 am

Re: Shake lua

kalis
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03.06.11 03:33:51 am

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addhook("hit","shake")
function shake(id,source,weapon)
     if itemtype(type,"dmg") >= 20 then
     parse("shake "..id.." 10") 
     elseif
     itemtype(type,"dmg") <= 19 then
     parse("shake "..id.." 5")
     end
end

when use else if only need end of last line

Re: Shake lua

J4x
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03.06.11 04:12:26 am

ok, thaks heocon, but try to learn english, don't use translators.

Re: Shake lua

kalis
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03.06.11 04:27:40 am

==. i so bad english

Re: Shake lua

J4x
User

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03.06.11 08:46:00 pm

Now it says me: Number expected got function

Re: Shake lua

Starkkz
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03.06.11 09:05:16 pm

Yep, it's truth. type is a function of Lua that returns in a string the type of a value. So, you should put "weapon" and not "type".

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addhook("hit","shake")
function shake(id,source,weapon)
	if itemtype(weapon,"dmg") >= 20 then
		parse("shake "..id.." 10")    
	elseif itemtype(weapon,"dmg") <= 19 then
		parse("shake "..id.." 5")
	end
end

Re: Shake lua

J4x
User

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04.06.11 12:39:52 am

Thank you so much

EDIT: i think it should be a number value, it says me that the number expected got nil.
EDIT2: I was wrong, this is my code fixed

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addhook("hit","shake")
function shake(id,source,weapon)
	if itemtype(id,"dmg") >= 20 then
	parse("shake "..id.." 10")
elseif 
	itemtype(id,"dmg") <= 19 then
	parse("shake "..id.." 5")
		end
	end

edited 3×, last 04.06.11 03:10:44 am

Re: Shake lua

Starkkz
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04.06.11 03:10:17 am

But the weapon with id 0 doesnt exist, how are you sure that it works?

Re: Shake lua

J4x
User

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04.06.11 03:12:38 am

I fixed it, DC wrote in the info.txt

itemtype(type,"value")

so he was wrong, the correct thing is

temtype(id,"value")

Re: Shake lua

Starkkz
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04.06.11 03:18:16 am

Actually not, if you put ID then it will mean about the id of the weapon in the list of current spawned weapons in the map or the weapon that someone (player) is using it in the moment. So he wrote type to make a difference of item type id.

well, in my opinion. both ways of explaination were wrong.

Re: Shake lua

J4x
User

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04.06.11 03:20:10 am

but if you use "type" you got an error, if you use "weapon" you also git an error, and actually id works for me.

Re: Shake lua

Starkkz
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04.06.11 03:26:29 am

Ah you were talking about the value to put in there when you call it?. But that shouldn't be incorrect, it's supposed that the weapon is a parameter wich returns the id of the weapon. so when you call the function itemtype, you have to insert the weapon parameter into the first required parameter for itemtype. Also put the second parameter to request the information needed,(dmg parameter). I don't know what goes wrong then.

Edit: maybe the weapon id parameter is wrong, because sometimes returns an id like 253 if is a building the one wich attacked you. That could be caused too in the case of doing slap at the admin panel.

Re: Shake lua

EngiN33R
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04.06.11 11:13:07 am

You have to use weapon type in itemtype(type,"value"), not the weapon ID. The weapon ID is the ID of the object, it can be 91, 253, whatever, while weapon type is actually what people call 'weapon IDs', so 45 for Laser etc. So you need to use the weapon parameter, which is the weapon type. Hope I helped.

Re: Shake lua

J4x
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04.06.11 05:15:16 pm

If I use "type" it says me: Bad argument to type#1(number expected got function), But if i use id it works.

Re: Shake lua

EngiN33R
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04.06.11 05:40:13 pm

Maybe it's because you don't have a variable called type? You know you have to declare a variable to use it, right? If you didn't declare type then it'll interpret it as the type function. You have to use the weapon argument.

Re: Shake lua

J4x
User

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04.06.11 05:57:58 pm

So you mean like:

itemtype(weapon,"dmg").

If that is wht you mean, i tryed it and it says me the that the number expected got nil.

edited 1×, last 04.06.11 09:28:14 pm

Re: Shake lua

Starkkz
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04.06.11 11:24:19 pm

that shouldn't be nil. In this case, why don't you try to use the hpdmg parameter of the lua function?

Re: Shake lua

J4x
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04.06.11 11:31:10 pm

Ok, I will use it...